Question

ai giải cho mình với

tìm x

a, \(\left(x-\frac{1}{2}\right)\cdot\frac{1}{3}+\frac{5}{7}=9\frac{5}{7}\)

b , \(\frac{1}{2}\cdot x+150\%\cdot x=2014\)

c, \(2-|\frac{3}{4}|=\frac{7}{12}\)

Answer 1

a) \(\left(x-\frac{1}{2}\right).\frac{1}{3}+\frac{5}{7}=9\frac{5}{7}\)

\(\left(x-\frac{1}{2}\right).\frac{1}{3}=9\frac{5}{7}-\frac{5}{7}\)

\(x-\frac{1}{2}=9:\frac{1}{3}\)

\(x=27+\frac{1}{2}\)

\(x=\frac{55}{2}\)

b)\(\frac{1}{2}.x+150\%.x=2014\)

\(\left(\frac{1}{2}+150\%\right)x=2014\)

\(2x=2014\)

\(x=2014:2\)

\(x=1007\)

c) \(2-\left|\frac{3}{4}\right|=\frac{7}{2}\)???????

Answer 2

và bài này nữa

tính nhanh

a, \(5\frac{7}{5}\cdot4\frac{2}{7}+5\frac{5}{7}\cdot4\frac{2}{7}\)

b, \(b,\frac{-7}{11}\cdot\frac{4}{19}+\frac{-7}{19}\cdot\frac{7}{11}+2\frac{7}{19}\)

cảm ơn giúp nhiều

Answer 3

\(a,\left(x-\frac{1}{2}\right)\frac{1}{3}+\frac{5}{7}=9\frac{5}{7}\)

\(\Rightarrow\frac{x}{3}-\frac{1}{6}+\frac{5}{7}=\frac{68}{7}\)

\(\Rightarrow\frac{x}{3}-\frac{1}{6}=\frac{63}{7}=9\)

\(\Rightarrow\frac{x}{3}=9+\frac{1}{6}=\frac{55}{6}\)

\(\Rightarrow x=55:2=27,5\)

\(b,\frac{1}{2}.x+150\%.x=2014\)

\(\Rightarrow\frac{x}{2}+\frac{3}{2}.x=2014\)

\(\Rightarrow2x=2014\)

\(\Rightarrow x=2014:2=1007\)

\(c,2-\left|\frac{3}{4}\right|=\frac{7}{12}\)

Answer 4

a, ( x-1/2).1/3+5/7=9 5/7

(x-1/2).1/3+5/7=68/7

( x-1/2).1/3=68/7-5/7

( x-1/2).1/3=9

x-1/2=9:1/3

x-1/2=9.3

x-1/2=27

x=27+1/2

x= 54/2 + 1/2

x= 55/2

b, 1/2.x +150%.x=2014

1/2.x+3/2.x=2014

x.(1/2+3/2)=2014

x.2=2014

x=2014:2

x=1007