\(A=\frac{72^3.54^2}{108^4}=\frac{\left(2^3.3^2\right)^3.\left(2.3^3\right)^2}{\left(2^2.3^3\right)^4}=\frac{2^9.3^6.2^2.3^6}{2^8.3^{12}}=\frac{2^{11}.3^{12}}{2^8.3^{12}}=\frac{2^{11}}{2^8}=2^3=8\)
\(\frac{2}{3}+\frac{3}{4}+\frac{4}{5}\) \(\frac{8}{5}+\frac{7}{6}+\frac{10}{9}\)
\(\frac{6}{5}+\frac{4}{3}+\frac{9}{7}\) \(\frac{90}{108}-\frac{40}{72}\)
b)tính
\(\frac{8}{9}-\frac{5}{6}\) \(\frac{90}{108}-\frac{40}{72}\)
\(\frac{15}{17}-\frac{11}{13}\)
A) 297+150:(493-47×10+7)
B) 728:(73×3.54+0.17×25+3.54×27+0.23×25
Tính giá trị biểu thức:
\(A=\frac{\frac{16}{10}:\left(1\frac{3}{5}\times \frac{5}{4}\right)}{\frac{64}{100}-\frac{1}{25}}+\frac{\left(\frac{108}{100}-\frac{2}{25}\right):\frac{4}{7}}{\left(5\frac{5}{9}-2\frac{1}{4}\right)\times 2\frac{2}{17}}+\frac{3}{5}\times \frac{1}{2}:\frac{2}{5}\)
Tính giá trị biểu thức sau :
\(A=\frac{\frac{16}{10}:\left(1\frac{3}{5}\times \frac{5}{4}\right)}{\frac{64}{100}-\frac{1}{25}}+\frac{\left(\frac{108}{100}-\frac{2}{25}\right):\frac{4}{7}}{\left(5\frac{5}{9}-2\frac{1}{4}\right)\times 2\frac{2}{17}}+\frac{3}{5}\times \frac{1}{2}:\frac{2}{5}\)
3.54 X 73 + 0.23 X 25 + 3.54 X 27 +0.77 X 25
A+B+C=108
A+B=48
A+C=72
Tim so a,b,c.
1.
\(\frac{1}{2}\)+\(\frac{2}{3}\)+\(\frac{3}{4}\)
\(\frac{4}{5}\)+\(\frac{4}{3}\)+\(\frac{6}{7}\)
\(\frac{1}{4}\)+\(\frac{2}{5}\)+\(\frac{1}{3}\)
\(\frac{3}{5}\)+\(\frac{5}{6}\)+\(\frac{7}{9}\)
\(\frac{8}{9}\)-\(\frac{5}{6}\)
\(\frac{99}{108}\)-\(\frac{40}{72}\)
\(\frac{16}{17}\)-\(\frac{12}{13}\)
\(\frac{99}{153}\)-\(\frac{75}{125}\)
3.54*73+25*0.23-3.54*27+0.17+25
Làm hộ mình nhé
