= \(\frac{35^3+13^3}{48}-35.13\)
=\(\frac{\left(35+13\right)\left(35^2-35.13+13^2\right)}{48}-35.13\)
=\(\frac{48.\left(35^2+13^2\right)-48.35.13-48.35.13}{48}\)
=352-2.35.13+132=(35-13)2=222=484
Vậy A = 484
\(A=\frac{35^3+13^3}{48}-35.13\)
\(A=\frac{42875+2197}{48}-455\)
\(A=939-455\)
\(A=484\)
THEO BÀI TA CÓ :
=> A=\(\frac{\left(35+13\right)^3}{48}\)-35.13
=> A = \(\frac{48^3}{48}\) -35.13
=> A = 483:48-35.13
=> A = 482-35.13
=> A = 2304-455
=> A = 1579
VẬY A = 1579