A=\(\frac{1}{2}\).\(\frac{2}{3}\)....\(\frac{2012}{2013}\)=\(\frac{1}{2013}\)
B=\(\frac{2012}{2012.2013}\)=\(\frac{1}{2013}\)
vậy A=B
\(A=\frac{1.2}{2.2}.\frac{2.3}{3.3}.\frac{3.4}{4.4}.\frac{4.5}{5.5}.....\frac{2012.2013}{2013.2013}=\frac{1}{2}.\frac{2}{3}.\frac{3}{4}.\frac{4}{5}....\frac{2012}{2013}=\frac{1.2.3.4.5....2012}{2.3.4.5....2013}=\frac{1}{2013}\)
\(B=\frac{2012.2013-2012.2012}{2012.2011+2012.2}=\frac{2012.\left(2013-2012\right)}{2012.\left(2011+2\right)}=\frac{2012}{2012.2013}=\frac{1}{2013}\)
\(\Rightarrow A=B\)
\(A=\frac{1.2}{2.2}.\frac{2.3}{3.3}.\frac{3.4}{4.4}.....\frac{2012.2013}{2013.2013}\)
\(A=\frac{1.2.2.3.3.4.....2012.2013}{2.2.3.3.4.4.....2013.2013}\)
\(A=\frac{1}{2013}\)
\(B=\frac{2012.2013-2012.2012}{2012.2011+2012.2}\)
\(B=\frac{2012.\left(2013-2012\right)}{2012.\left(2011+2\right)}\)
\(B=\frac{1}{2013}\)
b không ghi đề bài nên mk chỉ có thể giúp b tính A,B thôi
\(A=\frac{\left(1.2.3...2012\right).\left(2.3.4.5...2013\right)}{\left(2.3.4.5...2013\right).\left(2.3.4.5...2013\right)}\)
\(A=\frac{1}{2013}\)
\(B=\frac{2012.2013-2012.2012}{2012.2011+2012.2}\)
\(B=\frac{2012.\left(2013-2012\right)}{2012.\left(2011+2\right)}\)
\(B=\frac{2012.1}{2012.2013}\)
\(B=\frac{1}{2013}\)
\(\)Nếu đề bài là so sanh thì đây:
Vì \(\frac{1}{2013}=\frac{1}{2013}\)
\(=>A=B\)