cho day ti so bang nhau \(\frac{2bz-3cy}{a}=\frac{3cx-az}{2b}=\frac{ay-2bx}{3c}\)
cmr\(\frac{x}{a}=\frac{y}{2b}=\frac{z}{3c}\)
Cho \(\frac{2bz-3cy}{a}=\frac{3cx-az}{2b}=\frac{ay-2bx}{3c}\)
CMR:\(\frac{x}{a}=\frac{y}{2b}=\frac{z}{3c}\)
Với a,b,c khác 0, cho dãy tỉ số bằng nhau\(\frac{2bz-3cy}{a}=\frac{3cx-az}{2b}=\frac{ay-2bx}{3c}\).Chứng minh:\(\frac{x}{a}=\frac{y}{2b}=\frac{z}{3c}\)
1 . Cho \(\frac{2bz-3cy}{a}=\frac{3cx-az}{2b}=\frac{ay-2bx}{3c}\)
Chứng minh \(\frac{x}{a}=\frac{y}{2b}=\frac{z}{3c}\)
2 . Cho \(\frac{1}{c}=\frac{1}{2}\left(\frac{1}{a}+\frac{1}{b}\right)\left(\forall a,b,c\ne0;b\ne c\right)\). CMR : \(\frac{a}{b}=\frac{a-c}{c-b}\)
Cho: \(\frac{2bz-3cy}{a}=\frac{3cx-az}{2b}=\frac{ay-2bx}{3c}\)
CMR: \(\frac{x}{a}=\frac{y}{2b}=\frac{z}{3c}\)
\(Cho\)
\(\frac{2bz-3cy}{a}=\frac{3cx-az}{2b}=\frac{ay-2bx}{3c}\)
\(CMR:\frac{x}{a}=\frac{y}{2b}=\frac{z}{3c}\)
Giải hộ mình đanh cần gấp
Cho \(\frac{2bz-3cy}{a}\text{=}\frac{3cx-az}{2b}\text{=}\frac{ay-2bx}{3c}\)
Chứng minh : \(\frac{x}{a}\text{=}\frac{y}{2b}\text{=}\frac{z}{3c}\)
Cho dãy số : \(\frac{2bz-3cy}{a}=\frac{3cx-az}{2b}=\frac{ay-2bx}{3c}\)
Chứng minh : \(\frac{x}{a}=\frac{y}{2b}=\frac{z}{3c}\)
Cho dãy tỉ số bằng nhau\(\frac{2bz-3cy}{a}=\frac{3cx-az}{2b}=\frac{ay-2bx}{3c}\)Chứng minh \(\frac{x}{a}=\frac{y}{2b}=\frac{z}{3c}\)