Question

ab \(\times\) 99 = aabb

Answer 1

\(\overline{ab}\times99=\overline{aabb}\)

\(=>\left(10\times a+b\right)\times99=a\times100\times11+11\times b\)

\(=>10\times a\times99+b\times99=a\times1100+11\times b\)

\(=>990a+99b=1100a+11b\)

\(=>110a=88b\)

\(=>5a=4b\)

Vậy \(a=4;b=5\)