\(\overline{aaa}+\overline{aa}+3a=1000\)
\(\Rightarrow100a+10a+a+10a+a+3a=1000\)
\(\Rightarrow125a=1000\)\(\Rightarrow a=1000:125=8\)
aaa+aa+a+a+a=a.a.a+a.a+3a=3a+2a+3a=8a=1000\(\Rightarrow\)a=1000:8=125
Ta có: aaa + aa + a + a + a = 1000
\(\Rightarrow100a+10a+a+10a+a+a+a+a=1000\)
\(\Rightarrow125a=1000\)
\(\Rightarrow a=1000\div125=8\)
Vậy a = 8
sai rui 125 vi aaa ko co dau ngang tren dau
aaa+aa+a+a+a = 1000
=ax125 =1000
a=1000:125
a=8
\(\overline{aaa}\)\(+\)\(\overline{aa}\)\(+\)\(\overline{a}\)\(+\)\(\overline{a}\)\(+\)\(\overline{a}\)
\(=100a+10a+10a+a+3a\)
\(=125a=1000=a=1000:125=8\)
