\(3x^2-3x\left(x-2\right)=36\)
\(\Rightarrow3x^2-3x^2+6x=36\)
\(\Rightarrow6x=36\)
\(\Rightarrow x=6\)
Vậy \(x=6\)
a,3x2-3x( x-2)=36
=> 3x^2-3x^2+6x=36
=> 6x=36
=> x=6
\(3x^2-3x\left(x-2\right)=36\)
\(3x^2-3x^2+6x=36\)
\(6x=36\)
\(x=36:6\)
\(x=6\)
\(3x^2-3x\left(x-2\right)=36\)
\(\Rightarrow3x^2-3x^2+6x=36\)
\(\Rightarrow6x=36\)
\(\Rightarrow x=36:6\)
\(\Rightarrow x=6\)
Vậy x = 6
_Chúc bạn học tốt_