Chào bạn, bạn hãy theo dõi câu trả lời của mình nhé!
Theo mình thì đề phải là \(A=3+\frac{3}{1+2}+\frac{3}{1+2+3}+\frac{3}{1+2+3+4}+...+\frac{3}{1+2+3+...+100}\).
Ta có :
\(A=3+\frac{3}{1+2}+\frac{3}{1+2+3}+\frac{3}{1+2+3+4}+...+\frac{3}{1+2+3+...+100}\)
\(=>A=3\left(1+\frac{1}{1+2}+\frac{1}{1+2+3}+\frac{1}{1+2+3+4}+...+\frac{1}{1+2+3+...+100}\right)\)
Đặt \(1+\frac{1}{1+2}+\frac{1}{1+2+3}+\frac{1}{1+2+3+4}+...+\frac{1}{1+2+3+...+100}\) là B. Ta có :
\(B=\)\(1+\frac{1}{1+2}+\frac{1}{1+2+3}+\frac{1}{1+2+3+4}+...+\frac{1}{1+2+3+...+100}\)
\(=>B=\frac{1}{1}+\frac{1}{\left(1+2\right)\cdot2:2}+\frac{1}{\left(1+3\right)\cdot3:2}+\frac{1}{\left(1+4\right)\cdot4:2}+...+\frac{1}{\left(1+100\right)\cdot100:2}\)
\(=>B=\frac{1}{1}+\frac{1}{3\cdot2:2}+\frac{1}{4\cdot3:2}+\frac{1}{5\cdot4:2}+...+\frac{1}{101\cdot100:2}\)
\(=>B=\frac{2}{1\cdot2}+\frac{2}{2\cdot3}+\frac{2}{3\cdot4}+\frac{2}{4\cdot5}+...+\frac{2}{100\cdot101}\)
\(=>B=2\left(\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+\frac{1}{4\cdot5}+...+\frac{1}{100\cdot101}\right)\)
\(=>B=2\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{100}-\frac{1}{101}\right)\)
\(=>B=2\left(1-\frac{1}{101}\right)\)
\(=>B=2\cdot\frac{100}{101}=\frac{200}{101}\)
\(=>A=3B=3\cdot\frac{200}{101}=\frac{600}{101}\)
Chúc bạn học tốt!
\(A=3+1+\frac{1}{2}+\frac{3}{10}+\frac{3}{5050}\)
\(A=\left(3+1\right)+\left(\frac{1}{2}+\frac{3}{10}+\frac{3}{5050}\right)\)
\(A=4+\frac{4043}{5050}\)
\(A=\frac{24243}{5050}\)
Tài Nguyễn Tuấn dùng dấu = dấu => ko đúng lắm
\(A=3+\frac{3}{1+2}+\frac{3}{1+2+3}+\frac{3}{1+2+3+4}+...+\frac{3}{1+2+3+...+100}\)
\(=>A=3\left(1+\frac{1}{1+2}+\frac{1}{1+2+3}+\frac{1}{1+2+3+4}+...+\frac{1}{1+2+3+...+100}\right)\)
ak thằng thế mù mày ghép dồng vs dòng dưới là m hỉu
