Ta có : \(\frac{333}{444}< 1\);\(\frac{444}{333}>1\)
\(\Rightarrow\frac{333}{444}< \frac{444}{333}\)hay A < B
Vậy A < B .
A < B
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ai tích mình mình tích lại cho
A=\(333^{444}\)
=\(111^{444}.3^{444}\)
=\(111^{333+111}.3^{4.111}\)
=\(111^{333}.111^{111}.\left(3^4\right)^{111}\)
=\(111^{333}.81^{111}.111^{111}\)
B=\(444^{333}\)
=\(111^{333}.4^{333}\)
=\(111^{333}.4^{3.111}\)
=\(111^{333}.\left(4^3\right)^{111}\)
=\(111^{333}.64^{111}\)
A= \(111^{333}.81^{111}.111^{111}\)
B=\(111^{333}.64^{111}\)
Mà \(81>64\)=> \(81^{111}>64^{111}\)=> \(111^{333}.81^{111}\)\(>111^{333}.64^{111}\)=>\(111^{333}.81^{111}.111^{111}\)\(>\)\(111^{333}.64^{111}\)=>\(A>B\)