Question

A=3^1+3^2+3^3+...+3^999

 

Answer 1

chiu thui 123=679+rrwqw

Answer 2

A = 3 ^ 1 + 3 ^ 2 + 3 ^ 3 + .... + 3 ^ 999

3A = 3 ^ 2 + 3 ^ 3 + 3 ^ 4 + ... + 3 ^ 1000

3A - A = ( 3 ^ 2 + 3 ^ 3 + 3 ^ 4 + ... + 3 ^ 1000 )

           - ( 3 ^ 1 + 3 ^ 2 + 3 ^ 3 + .... + 3 ^ 999 )

2A      = 3 ^ 1000 - 3

A        = \(\frac{3^{1000}-3}{2}\)

Answer 3

\(A=3+3^2+3^3+...+3^{999}\)

\(3A=3^2+3^3+3^4+...+3^{1000}\)

\(3A-A=\left(3^2+3^3+3^4+...+3^{1000}\right)-\left(3+3^2+3^3+...+3^{999}\right)\)

\(2A=3^{1000}-3\)

\(A=\frac{3^{1000}-3}{2}\)