Question

a,1 phần 2 trừ 3 phần 4 nhân (âm 6 phần 5)

b, 3 phần 8 + 2²- 3 phần 8

Answer 1

\(a,\)\(\frac{1}{2}-\frac{3}{4}.\frac{-6}{5}\)

\(=\frac{1}{2}-\frac{-9}{10}\)

\(=\frac{1}{2}+\frac{9}{10}\)

\(=\frac{7}{5}\)

\(b,\frac{3}{8}+2^2-\frac{3}{8}\)

\(=\left(\frac{3}{8}-\frac{3}{8}\right)+2^2\)

\(=0+4\)

\(=4\)

Answer 2

a) \(\frac{1}{2}-\frac{3}{4}.\left(-\frac{6}{5}\right)\)\(=\frac{1}{2}-\left(-\frac{9}{10}\right)\)\(=\frac{1}{2}+\frac{9}{10}=\frac{5}{10}+\frac{9}{10}=\frac{14}{10}=\frac{7}{5}\)

b) \(\frac{3}{8}+2^2-\frac{3}{8}=\frac{3}{8}+4-\frac{3}{8}=\frac{3}{8}-\frac{3}{8}+4=0+4=4\) 

Hoặc \(\frac{3}{8}+2^2-\frac{3}{8}=\frac{3}{8}+4-\frac{3}{8}=\frac{3}{8}+\frac{32}{8}-\frac{3}{8}=\frac{35}{8}-\frac{3}{8}=\frac{32}{8}=4\)