x(x+1)-x(x-3)=0
=>x2+x-x2+3x=0
=>4x=0
=>x=0
vậy x=0 thì x(x+1)-x(x-3)=0
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tìm x: part 1 : a,(x^3)^2-(x+1)(x-1)=1 b,(x-2)^2-3(x-2)=0 c,(x+2)(x^2-2x+4)-x(x^2+2)=15 d,(x+1)^2-(x+1)(x-2)=0 e,4x(x-2017)-x+2017=0 f,(x+4)^2-16=0 part 2: a,x^3+27+(x+3)(x-9)=0 b,(2x-1)^2-4x^2+1=0 c,2(x-3)+x^2-3x=0 d,x^2-2x+1=6x-6 e,x^3-9x=0
a,x+5/x-1+8/x^2-4x+3=x+1/x-3 b,x-4/x-1-x^2+3/1-x^2+5/x+1=0 c,3x/4-5=3-x/2+5x-1/6 d,(x-2)(x+2)-(x-3)(x+4)-2x+3=0 e,(x-1)^2+2(x+1)=5x+5 g,(x-3)(x+4)x=0
tìm x bt a) x^3=x^5 b) 4x.(x+1)=(x+1) c) x.(x-1)-2(1-x)=0 d) 2x.(x-2)-(2-x)^2 e) (x-3)^2+3-x=0 f) 5x.(x-2)-(2-x)=0
Tìm x
a)x^2-x-1/4=0
b)x(x-2)x-2=0
c)5x(x-3)-x+3=0
d)x^3-1/4x=0
e)(2x-1)^2-(x+3)=0
giúp e nha
Bài 5: Tìm x (Giải phương trinh)
a)x^3-13x=0
b) 5x(x – 2000) – x + 2000 = 0
c) 2x(x – 2) + 3(x – 2) = 0
d) x + 1 = (x + 1)2
e) x + 5x2 = 0
f) x3 + x = 0
Bài 5: Tìm x (Giải phương trình)
a)x^3-13x=0 b) 5x(x – 2000) – x + 2000 = 0
c) 2x(x – 2) + 3(x – 2) = 0 d) x + 5x2 = 0
d) x + 1 = (x + 1)2 e) x3 + x = 0
Tìm x
a,x(x-2)-x(x-1)(x-3)=0
b,(2x-5).(x+3)-(x-1).(2x+3)=0
c,(x-2)(x^2+2x+8)-x^3-2x+1=0
1) Tim x
a) 3x(x-1)+x-1=0
b)2(x+3)-x^2-3x=0
làm tương tự như bài này nè!
x(x-2)+x-2=0
=>x*((x-2)-x-3)=0
=>(x-2)(x+10=0
hoac x-3=0 =>x=3
hoac 5x-1=0 =>x=1 phan 5
vậy x = 1 phần 5 ;x=3
hoac 5x-1=0 => x=1 phan 5
chứng minh nếu a^3 +b^3+c^3=3abc thì a+b+c=0 hoặc a=b=c
a, x(x+3) - 3(x^2+1)=x+1-x(x-2)
b, (x-3)(x-2)-(x+1)(x-5)=0
Tìm x, biết:a) 2-x 2
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3
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- 72x 0;c)
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Đọc tiếp
Tìm x, biết:
a) 2-x = 2 ( x - 2 ) 3 ; b) 8 x 3 - 72x = 0;
c) ( x - 1 , 5 ) 6 + 2 ( 1 , 5 - x ) 2 = 0; d) 2 x 3 +3 x 2 +3 + 2x = 0;
e) x 3 - 4x- 14x(x - 2) = 0; g) x 2 (x + 1)- x(x + 1) + x(x - 1) = 0.
a. 2x – 3 = 4x + 6 b. x 2 1 x x 3 4 8 = 0 c. x(x – 1) + x(x + 3) = 0 d. x x 2x 2x 6 2x 2 (x 1)(x 3)