a)|x-75|+3=15
|x-75|=12
\(\Rightarrow\orbr{\begin{cases}x-75=12\\x-75=-12\end{cases}\Rightarrow}\orbr{\begin{cases}x=87\\x=63\end{cases}}\)
b)\(\left[\left(x^2+25\right)-13\right].3=36\)
\(\left[\left(x^2+25\right)-13\right]=108\)
\(\left(x^2+25\right)=121\)
\(x^2=96\)
x ko TM
a) |x-75|+3=15
|x-75| =15-3
|x-75| = 12
|x| =12+75
|x| = 87
b) [(\(x^2\)+25)-13].3=36
[(x^2 + 25)-13] =36:3
(x^2 +25)-13 =12
(x^2 +25) =12+13
x^2 +25 =25
x^2 =25-25
x^2 =0
x^2 =0^2