Ta có: a x 2/3 + a x 7/3 = 9
a x (2/3+7/3) = 9
a x 3=9
a=9:3
a=3
Theo đề bài, có:
\(a.\frac{2}{3}+a:\frac{3}{7}=9\)
\(a.\frac{2}{3}+\frac{a.}{ }\frac{7}{3}=9\)
\(a\left(\frac{2}{3}+\frac{7}{3}\right)=9\)
\(a.3=9\Leftrightarrow a=9:3=3\)
a x 2/3 + a : 3/7 = 9
a x 2/3 + a x 7/3 = 9
a x ( 2/3 + 7/3 ) = 9
a x 9/3 = 9
a x 3 = 9
a = 9 : 3
a = 3
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