\(90⋮x,150⋮x\Rightarrow x\inƯC\left(90;150\right)\)
\(90=2.3^2.5\)
\(150=2.3.5^2\)
\(ƯCLN\left(90;150\right)=2.3.5=30\)
\(\Rightarrow x\inƯ\left(ƯCLN\left(90;150\right)\right)=Ư\left(30\right)=\left\{1;2;3;5;6;10;15;30\right\}\)
Mà 5 < x < 30 nên \(x\in\left\{6;10;15\right\}\)
b, \(102⋮x,54⋮x\) mà x lớn nhất nên \(x=ƯCLN\left(102;54\right)\)
\(102=2.3.17\)
\(54=2.3^3\)
\(ƯCLN\left(102;54\right)=2.3=6\)
Vậy x lớn nhất bằng 6