Các câu hỏi tương tự
a) so sánh
\(\sqrt{17}+\sqrt{26}+1\) và \(\sqrt{99}\)
b) CMR
\(\frac{1}{\sqrt{1}}+\frac{1}{\sqrt{2}}+\frac{1}{\sqrt{3}}+...+\frac{1}{\sqrt{100}}>10\)
a)so sánh:sqrt{17}+sqrt{26}+1vàsqrt{99}b)chứng minh:frac{1}{sqrt{ }1}+frac{1}{sqrt{ }2}+frac{1}{sqrt{ }3}+...+frac{1}{sqrt{ }99}+frac{1}{sqrt{ }100}10c)cho:S1-frac{1}{2}+frac{1}{3}-frac{1}{4}+...+frac{1}{2013}-frac{1}{2014}+frac{1}{2015}vàPfrac{1}{1008}+frac{1}{1009}+frac{1}{1010}+...+frac{1}{2014}+frac{1}{2015}tính left(S-Pright)^{2016}
Đọc tiếp
a)so sánh:
\(\sqrt{17}+\sqrt{26}+1và\sqrt{99}\)
b)chứng minh:\(\frac{1}{\sqrt{ }1}+\frac{1}{\sqrt{ }2}+\frac{1}{\sqrt{ }3}+...+\frac{1}{\sqrt{ }99}+\frac{1}{\sqrt{ }100}>10\)
c)cho:S=\(1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{2013}-\frac{1}{2014}+\frac{1}{2015}\)vàP=\(\frac{1}{1008}+\frac{1}{1009}+\frac{1}{1010}+...+\frac{1}{2014}+\frac{1}{2015}\)tính \(\left(S-P\right)^{2016}\)
a, so sánh: \(\sqrt{17}+\sqrt{26}+1\)và \(\sqrt{99}\)
b, CMR: \(\frac{1}{\sqrt{1}}+\frac{1}{\sqrt{2}}+...+\frac{1}{\sqrt{100}}\)>10
a) So sánh: \(\sqrt{17}\)+ \(\sqrt{26}\)+1 và \(\sqrt{99}\)
b) CMR: \(\frac{1}{\sqrt{1}}\)+\(\frac{1}{\sqrt{2}}\)+\(\frac{1}{\sqrt{3}}\)+....+\(\frac{1}{\sqrt{100}}\)>10
a) So sanh: \(\sqrt{17}+\sqrt{26}+1\)va \(\sqrt{99}\)
b) CMR: \(\frac{1}{\sqrt{1}}+\frac{1}{\sqrt{2}}+\frac{1}{\sqrt{3}}+...+\frac{1}{\sqrt{100}}>10\)
So sánh
a) \(\sqrt{17}+\sqrt{26}+1và\sqrt{99}\)
b) \(\frac{1}{\sqrt{1}}+\frac{1}{\sqrt{2}}+...+\frac{1}{\sqrt{100}}và10\)
Chứng minh rằng a,\(\sqrt{2}+\sqrt{6}+\sqrt{12}+\sqrt{20}+\sqrt{30}+\sqrt{42}< 24\)
b,\(\frac{1}{\sqrt{1}}+\frac{1}{\sqrt{2}}+\frac{1}{\sqrt{3}}+...+\frac{1}{\sqrt{100}}>10\)
Chung minh rang A=\(1+\frac{1}{\sqrt{2}}+\frac{1}{\sqrt{3}}+\frac{1}{\sqrt{4}}+...+\frac{1}{\sqrt{99}}+\frac{1}{\sqrt{100}}>10\)>10
Giúp mik với
Ko dùng máy tinnhs,hãy so sánh các số sau
a.\(\sqrt{15}+2\)và \(7\)
b.\(\sqrt{26}-5\)và\(3-\sqrt{10}\)
c.\(\frac{1}{\sqrt{1}}+\frac{1}{\sqrt{2}}+\frac{1}{\sqrt{3}}+...+\frac{1}{\sqrt{100}}\)và 10