\(\frac{\left(-5\right)^3\cdot40\cdot4^3}{135\cdot\left(-2\right)^{14}\cdot\left(-100\right)^0}\)
a)\(\frac{-135}{540}\)
b)\(\frac{25.13}{26.35}\)
c)\(\frac{6.9-2.17}{63.3-119}\)
d)\(\frac{3.13-13.18}{15.40-80}\)
e)\(\frac{-5^3.40.4^4}{135.\left(-2\right)^{14}.\left(-100\right)^0}\)
f)\(\frac{2929-101}{2.1919+404}\)
g)\(\frac{-1997.1996+1}{\left(-1995\right).\left(-1997\right)+1996}\)
h)\(\frac{2.3+4.6+14.21}{3.5+6.10+21.35}\)
i)\(\frac{3.7.13.37.39-10101}{505050-70707}\)
k)\(\frac{18.34+\left(-18\right).124}{-36.17+9.\left(-52\right)}\)
\(\frac{-1997\cdot1996+1}{\left(-1995\right)\cdot\left(-1997\right)+1996}\)
Rút gọn các phân số sau
a,\(\frac{6.9-2.17}{63.3-119}\)b,\(\frac{3.13-13.18}{15.40-80}\) c,\(\frac{-1997.1996+1}{\left(-1995\right).\left(-1997\right)+1996}\)
d,\(\frac{3.7.13.37.39-10101}{505050-70707}\)
e,\(\frac{2929-101}{2.1919+404}\)
Rút gọn phân số:
a)\(\frac{2929-101}{2.1919+404}\)
b)\(\frac{-1997.1996+1}{-1995.\left(-1997\right)+1996}\)
c)\(\frac{2.3+4.6+14.21}{3.5+6.10+21.35}\)
d)\(\frac{3.7.13.37.39-10101}{505050-70707}\)
e)\(\frac{18.34+\left(-18\right).124}{-36.17+9.\left(-52\right)}\)
Bài 1:Rút gọn phân số
a)\(\frac{-2019\cdot2018+1}{\left(-2017\right)\cdot\left(-2019\right)+2018}\)
b)\(\frac{6\cdot9-2\cdot7}{63\cdot3-119}\)
c)\(\frac{2929-101}{2\cdot1919+404}\)
d)\(\frac{2\cdot3+4\cdot6+14\cdot21}{3\cdot5+6\cdot10+21\cdot35}\)
Rút gọn phân số
\(y=\frac{\left(-5\right)^3.40.4^3}{135.\left(-2\right)^{14}.1}\) ; \(\frac{2929-101}{2.1919+404}\) ; \(\frac{-1997.1996+1}{-1995.\left(-1997\right)+1996}\)
Chứng minh rằng:
a)\(\frac{1\cdot3\cdot5\cdot\cdot\cdot39}{21\cdot22\cdot23\cdot\cdot\cdot40}=\frac{1}{2^{20}}\)
b)\(\frac{1\cdot3\cdot5\cdot\cdot\cdot\left(2n-1\right)}{\left(n+1\right)\left(n+2\right)\left(n+3\right)\cdot\cdot\cdot2n}=\frac{1}{2^n}\)Với \(n\inℕ^∗\)
Tính nhanh :
\(A=\left(1-\frac{2}{6\cdot7}\right)\left(1-\frac{2}{7\cdot8}\right)\left(1-\frac{2}{8\cdot9}\right)\cdot\cdot\cdot\left(1-\frac{2}{51\cdot52}\right)\)
\(B=\left(1+\frac{1}{1\cdot3}\right)\left(1+\frac{1}{2\cdot4}\right)\left(1+\frac{1}{3\cdot5}\right)\cdot\cdot\cdot\left(1+\frac{1}{99\cdot101}\right)\)