Các câu hỏi tương tự
\(\left(\frac{112}{13.20}+\frac{112}{20.27}+\frac{112}{27.34}+....+\frac{112}{62.69}\right):\left(-\frac{5}{9.13}-\frac{7}{9.25}-\frac{13}{19.25}-\frac{31}{19.69}\right)\)
\(\left(\frac{112}{13.20}+\frac{112}{20.27}+\frac{112}{27.34}+...+\frac{112}{62.69}\right)\) \(:\left(-\frac{5}{9.13}-\frac{7}{9.25}-\frac{13}{19.25}-\frac{31}{19.69}\right)\)
A = (\(\frac{112}{13.20}+\frac{112}{20.27}+\frac{112}{27.34}+...+\frac{112}{62.69}\)) : \(\frac{-5}{9.13}-\frac{-7}{9.25}+\frac{-13}{19.25}+\frac{-31}{19.69}\))
Cố gắng giúp mik với nhé
Tính
(\(\frac{112}{13.20}+\frac{112}{20.27}+\frac{112}{27.34}+...+\frac{112}{62.64}\))
: (\(\frac{-5}{9.13}-\frac{7}{9.25}-\frac{13}{19.25}-\frac{31}{19.69}\)
Tính \(A=\left(\frac{112}{13.20}+\frac{112}{20.27}+...+\frac{112}{62.69}\right)\div\)\(\left(\frac{-5}{9.13}-\frac{7}{9.25}-\frac{13}{19.25}-\frac{31}{19.69}\right)\)
Tính
\(E=\left(\frac{112}{13.20}+\frac{112}{20.27}+...+\frac{112}{62.69}\right):\left(-\frac{5}{9.3}-\frac{7}{9.25}-\frac{13}{19.25}-\frac{31}{19.69}\right)\)
tính :
C=(112/13.20+112/20.27+112/27.34+...+112/62.69):(-5/9.13-7/9.25-13/19.25-31/19.69)
Rút gọn
A = \(\frac{\frac{2}{39}-\frac{1}{15}-\frac{2}{153}}{\frac{1}{34}+\frac{3}{20}-\frac{3}{26}}\): \(\frac{1+\frac{2}{71}-\frac{5}{121}}{\frac{65}{121}-\frac{26}{71}-13}\)
B = ( \(\frac{112}{13.20}+\frac{112}{20.27}+\frac{112}{27.34}+...+\frac{112}{62.69}\)) :( \(-\frac{5}{9.13}-\frac{7}{9.25}-\frac{13}{19.25}-\frac{31}{19.69}\))
1)Tinh
a)\(A=\left(\frac{112}{13.20}+\frac{112}{20.27}\frac{112}{27.34}+...+\frac{112}{62.69}\right):\left(-\frac{5}{9.13}-\frac{7}{9.25}-\frac{13}{19.15}-\frac{31}{19.69}\right)\)
b)\(B=\frac{2.2012}{1+\frac{1}{1+2}+\frac{1}{1+2+3}+\frac{1}{1+2+3+4}+...+\frac{1}{1+2+3+...+2012}}\)