a) \(\dfrac{5}{2\sqrt{3}}=\dfrac{5\sqrt{3}}{2\sqrt{3}\sqrt{3}}=\dfrac{5\sqrt{3}}{2\cdot3}=\dfrac{5}{6}\sqrt{3}\)
b) \(\dfrac{10}{\sqrt{3}+1}=\dfrac{10\left(\sqrt{3}+1\right)}{\left(\sqrt{3}+1\right)\left(\sqrt{3}-1\right)}=\dfrac{10\left(\sqrt{3}-1\right)}{3-1}=5\left(\sqrt{3}-1\right)\)
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