a, cho day ti so bang nhau : \(\frac{2a+b+c+d}{a}=\frac{a+2b+c+d}{b}=\frac{a+b+2c+d}{c}=\frac{a+b+c+2d}{d}\)
tinh gia tri bieu thuc M: \(\frac{a+b}{c+d}+\frac{b+c}{d+a}+\frac{c+d}{a+b}+\frac{d+a}{b+c}\)
b,cho x= \(1+\frac{1}{2013}+\frac{1}{2013^2}+\frac{1}{2013^3}+....+\frac{1}{2013^{2013}}\)
tinh gia tri bieu thuc: S= (2012x+\(\frac{1}{2013^{2013}}\)) : 2013^2014
cho day ti so bang nhau
\(\frac{2a+b+c+d}{a}=\frac{a+2b+c+d}{b}=\frac{a+b+2c+d}{c}=\frac{a+b+c+2d}{d}\)
tinh gia tri bieu thuc m=\(\frac{a+b}{c+d}=\frac{b+c}{d+a}=\frac{c+d}{a+b}=\frac{d+a}{b+c}\)
cho day ti so bang nhau :
\(\frac{2a+b+c+d}{a}=\frac{a+2b+c+d}{b}=\frac{a+b+2c+d}{c}=\frac{a+b+c+2d}{d}\)
tim gia tri bieu thuc:m=\(\frac{a+b}{c+d}+\frac{b+c}{d+a}+\frac{c+d}{a+b}+\frac{d+a}{b+c}\)
cho \(\frac{a}{b}=\frac{c}{d}\) CMR
a, \(\frac{c+d}{a+b}=\frac{c}{a}\)
b, \(\left(\frac{a-b}{c-d}\right)^{2013}=\frac{a^{2013}+b^{2013}}{c^{2013}+d^{2013}}\)
cho \(\frac{a}{b}=\frac{c}{d}\) CM \(\frac{a^{2013}}{c^{2013}}=\frac{b^{2013}}{d^{2013}}=\left(\frac{a-b}{c-d}\right)^{2013}\)
bai 1
xac dinh dau cua c ,biet rang 2a\(^3\)bc trai dau voi -3a\(^5\)b\(^3\)c\(^2\)
bai 2
cho day ti so bang nhau
\(\frac{2a+b+c+d}{a}=\frac{a+2b+c+d}{b}=\frac{a+b+2c+d}{c}=\frac{a+b+c+2d}{d}\)
tinh gia tri bieu thuc m voi
m=\(\frac{a+b}{c+d}=\frac{b+c}{d+a}=\frac{c+d}{a+b}=\frac{d+a}{b+c}\)
bài1)tính: \(A=\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2014}}{2013+\frac{2013}{2}+\frac{2012}{3}+...+\frac{1}{2014}}\)
bài 2) cho\(\frac{a}{b}< \frac{c}{d}\) và\(b;d>0\)
CHỨNG MINH RẰNG: \(\frac{a}{b}< \frac{a+c}{b+d}< \frac{c}{d}\)
CÁC BẠN GIÚP CHI NHÉ!!!!! MINK SE LIKE CHO!!!
cho\(\frac{a}{b}\)=\(\frac{c}{d}\)chứng minh rằng
\(\left(\frac{a-b}{c-d}\right)^{2013}\)=\(\frac{a^{2013}+b^{2013}}{c^{2013+}d^{2013}}\)
cho tỉ lệ thức\(\frac{a}{b}=\frac{c}{d}\)chứng minh \(\frac{2.a^{2013}+5.b^{2013}}{2.c^{2013}+5.d^{2013}}=\frac{\left(a+b\right)^{2013}}{\left(c+d\right)^{2013}}\)ghi cách giải lớp 7, dễ hiểu (ai nhanh thì tk)
Biet \(\frac{-a+b+c+d}{a}=\frac{a-b+c+d}{b}=\frac{a+b-c-d}{c}=\frac{a+b+c-d}{d}\)
Tinh gia tri bieu thuc \(\left(\frac{a}{b}+1\right).\left(\frac{b}{c}+1\right).\left(\frac{c}{d}+1\right).\left(1+\frac{d}{a}\right)\)
