Cho 2 số thực a,b thỏa mãn: lal khác lbl va ab khac 0 thoa man \(\frac{a-b}{a^2+ab}+\frac{a+b}{a^2-ab}=\frac{3a-b}{a^2-b^2}\)
Tính P=\(\frac{a^3+2a^2b+2b^3}{2a^3+ab^2+2b^3}\)
cho a khac 0 b khac 0 va a+b=1 chung minh rang \(\frac{b}{a^3-1}-\frac{a}{b^3-1}=\frac{2\left(a-b\right)}{a^2b^2+3}\)
Giai va bien luan cac phuong trinh sau:
1. \(\frac{a+b-x}{c}+\frac{a+c-x}{b}+\frac{b+c-x}{a}+\frac{4x}{a+b+c}=1\)
(an x) voi dk; a,b,b khac 0 va a+b+c khac 0
2.\(\frac{x-a}{bc}+\frac{x-b}{ac}+\frac{x-c}{ab}=2\left(\frac{1}{a}+\frac{1}{b}+\frac{1}{c}\right)\)
(an x) voi dk: a,b,c khac 0
3, \(\frac{mx+3}{6}+\frac{m^2-1}{2}=\frac{x+5}{10}+\frac{2}{5}\left(x+m^2+1\right)\)
(an x)
a,b khac 0 sao cho a + \(\frac{1}{b}=1\) va \(a^2+\frac{1}{b^2}=3\) Tinh \(N=\frac{a^4b^4+a^2b^2+1}{b^4}\)
cho ba so a,b,c khac 0 thoa man ab+bc +ac = 0 .tinh B=bc/a2 + ca/b2 + ab/c2
mk can cau tra loi ngay mong moi nguoi giup do
Cho ab(x^2+y^2)+xy(a^2+b^2)=ab trong do a khac 0, b khac 0 a+b=1
CMR:a=b
cho 2 so thuc a va b khac 0 thoa man 2a2 +b2/4 +1/a2=4
cho a,b,c khac 0 va \(a^3b^3+b^3c^3+c^3a^3=3a^2b^2c^2\).tinh P= \(\left(1+\frac{a}{b}\right)\left(1+\frac{b}{c}\right)\left(1+\frac{c}{a}\right)\)
Cho a,b,c tung doi 1 khac nhau thoa man: ab+bc+ac=1
Tinh: A= [(a+b)2 (b+c)2 (a+c)2] / [(1+a2)(1+b2)(1+c2)]