a) \(5^{-1}.25^x=125\)
\(\Rightarrow5^{-1}.5^{2x}=5^3\)
\(\Rightarrow5^{2x-1}=5^3\)
\(\Rightarrow2x-1=3\)
\(\Rightarrow2x=4\)
\(\Rightarrow x=2\)
Vậy \(x=2\)
b) \(|x+1|+|x+2|+|x+3|=4x\)
Vì \(\hept{\begin{cases}|x+1|\ge0\forall x\\|x+2|\ge0\forall x\\|x+3|\ge0\forall x\end{cases}}\)
\(\Rightarrow|x+1|+|x+2|+|x+3|\ge0\)
\(\Rightarrow4x\ge0\)
\(\Rightarrow x\ge0\)
\(\Rightarrow\hept{\begin{cases}x+1>0\\x+2>0\\x+3>0\end{cases}}\)
\(\Rightarrow\hept{\begin{cases}|x+1|=x+1\\|x+2|=x+2\\|x+3|=x+3\end{cases}}\)
\(\Rightarrow\left(x+1\right)+\left(x+2\right)+\left(x+3\right)=4x\)
\(\Rightarrow3x+6=4x\)
\(\Rightarrow x=6\)
Vậy \(x=6\)