Question

a) 3.(x-2)+99=144

b) 5.(x-12)=40

c) 16+4.(x-1)=96

Answer 1

\(3.\left(x-2\right)+99=144\)

\(=>3.\left(x-2\right)=144-99\)

\(=>3.\left(x-2\right)=45\)

\(=>x-2=45:3\)

\(=>x-2=15\)

\(=>x=17\)

vậy \(x=17\)

b) \(5.\left(x-12\right)=40\)

\(=>x-12=40:5\)

\(=>x-12=8\)

\(=>x=20\)

vậy \(x=20\)

c) \(16+4.\left(x-1\right)=96\)

\(=>4.\left(x-1\right)=96-16\)

\(=>4.\left(x-1\right)=80\)

\(=>x-1=80:4\)

\(=>x-1=20\)

\(=>x=21\)

vậy \(x=21\)

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Answer 2

a) x = 17

b) x = 20

c) x = 21