Tìm x biết :
a, 4.(18 - 5x) - 12.(3x - 7) = 15.(2x - 16) - 6(x + 14)
b, 5.(3x + 5) - 4.(2x - 3) = 5x + 3.(2x + 12) + 1
c, 2.(5x - 8) - 3.(4x - 5) = 4.(3x - 4) + 11
d, (3x + 2)(2x + 9) - (x + 2)(6x + 1) = (x + 1) - (x - 6)
e, (8x - 3)(3x + 2) - (4x + 7)(x + 4)= (2x + 1)(5x - 1) - 33
Tìm x biết:
a) 4(18-5x) - 12(3x-7) = 15(2x-16) - 6(x+14)
b) 5(3x+5) - 4(2x-3) = 5x+3(2x+12)+1
c)2(5x-8) - 3(4x-5) = 4(3x-4) + 11
d) 5x-3 {4x-2 [4x-3(5x-2)]}=182
x+ 1/15 x+ 2/7 x+ 4/4 + 6 = 0
x+ 2/13 2x+ 45/15 = 3x+ 8/37+ 4x+69/9
7.1 cho f (x) = X^5 + 3x^2-5x^3-x^7+x^3+2x^2+X^5-4x^2+2x^7
cho g(x)=x^4+4x^3-5x^8-x^7+x^3+x^2-2x^7+x^4- 4x^2-x^8
Tìm x, biết :
1) x+1 / x-2 = 3/4
2) 2x - 3 / x+1 = 4/7
3) 2x + 3 / 7 = 4x-1/15
4) 11x - 2 / 7x + 5 = 11/8
5) 12 - 7x / -13 = 4 - 3x / -5
tìm x biết
a, ! 5/4x - 7/2 ! - ! 5/8 + 3/5 ! =0
b,! 11/5 -x ! + ! x - 1/5 ! + 41/5 = 12
c,! x - 2! + ! x - 3! + ! x - 4! = 2
d,3x!x + 1! -2x! x+ 2! = 12
e,! 2x + 5 - !3x - 2! ! = 3x + 7
f,! !3x + 2! +3x2! = 4x + 3x2
CÁC BẠN GIÚP MÌNH NHA NHA NHA! THỨ 4 MÌNH NỘP RỒI.DẤU (!) LÀ GIÁ TRỊ TUYỆT ĐỐI NHA!SAU NÀY MÌNH SẼ LIKE CHO
Tìm x:\(a,\frac{6x-5}{-7}=\frac{5x-3}{-5}\\ b,\frac{12-7x}{-13}=\frac{4-3x}{-5}\\ c,\frac{2x+4}{7}=\frac{4x-2}{15}\)
a, |x-1\2|+2x=6
b, 3x+|2\3-x|+2=0
c, 7x+6+|3x-18|=x-1
d,4x-|8-4x|-6=0
e,12-|3x-4|=8-2x
p(x)=3x^2+7+2x^4-3x^2-4-5x+2x^3
Q(x)=-3x^3+2x^2-x^4+x+x^3+4x-2+5x^4
tính p(x) + Q(x)