Question

 

A = 2002+2004+2006+...+2014/ 1/3x4+1/4x5+1/5x6+...+1/20x21

Answer 1

\(A=\frac{2002+2004+2006+...+2014}{\frac{1}{3x4}+\frac{1}{4x5}+\frac{1}{5x6}+...+\frac{1}{20x21}}\)

\(A=\frac{\left(2014+2002\right)x7:2}{\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+...+\frac{1}{20}-\frac{1}{21}}\)

\(A=\frac{14056}{\frac{1}{3}-\frac{1}{21}}\)

\(A=\frac{14056}{\frac{2}{7}}\)

\(A=14056:\frac{2}{7}\)

\(A=49196\)