a, Ta có : \(\frac{15}{x-1}\in Z\Leftrightarrow x-1\inƯ_{15}=\left\{-15;-5;-3;-1;1;3;5;15\right\}.\)
\(\Rightarrow x=\left\{-14;-4;-2;0;2;4;6;16\right\}\)
b, Ta có : \(\frac{x+6}{x-1}=\frac{x-1+7}{x-1}=\frac{x-1}{x-1}+\frac{7}{x-1}=1+\frac{7}{x-1}\)
Mà 1 thuộc Z => \(\frac{7}{x-1}\in Z\Leftrightarrow x-1\inƯ_7=\left\{-7;-1;1;7\right\}\)
\(\Rightarrow x=\left\{-6;0;2;8\right\}\)
C, tự làm nha