Ta có :
\(9^x.81^x=3^{2010}\)
\(\left(3^2\right)^x.\left(3^4\right)^x=3^{2010}\)
\(3^{2x}.3^{4x}=3^{2010}\)
\(3^{2x+4x}=3^{2010}\)
=> 2x + 4x = 2010
=> 6x = 2010
x = 2010 : 6
x = 335
Vậy x = 335
Ủng hộ mk nha !!! ^_^
\(9^x.81^x=3^{2010}\)
\(3^{2x}.3^{4x}=3^{2010}\)
\(3^{2x+4x}=3^{2010}\)
\(3^{6x}=3^{2010}\)
=> 6x = 2010
=> x = 2010 : 6
x = 335
\(\text{9^x.81^x=3}^{2010}\)
\(\Leftrightarrow\)9x.92x=91005
\(\Leftrightarrow\)93x=91005
\(\Leftrightarrow\)x=1005/3=335