\(9^{2+2+1}=9^5\)
\(3^5.2^5=\left(3.3.3.3.3\right).\left(2.2.2.2.2\right)=\left(3.2\right).\left(3.2\right).\left(3.2\right).\left(3.2\right).\left(3.2\right)=6.6.6.6.6=6^5\)
Tích nha mik tích lại
thanks nhiều
\(9^2.9^9=\)
\(2^2.2^4=\)
\(3^4:3^2=\)
AI TÍCH MIK , MIK TÍCH LẠI
THỀ LUÔN
3.Tính hợp lí:
a,\(\frac{17}{5}.\frac{-31}{125}.\frac{1}{2}.\frac{10}{17}.\frac{-1}{2^3}\)
b,\(\left(\frac{11}{4}.\frac{5}{9}-\frac{4}{9}.\frac{11}{4}\right).\frac{8}{33}\)
c,\(\left(\frac{17}{28}+\frac{18}{29}-\frac{19}{30}-\frac{20}{31}\right).\left(\frac{-5}{12}+\frac{1}{4}+\frac{1}{6}\right)\)
4.Tìm tích:
a,\(\left(\frac{1}{2}+1\right)\left(\frac{1}{3}+1\right).....\left(\frac{1}{99}+1\right)\)
b,\(\left(\frac{1}{2}-1\right)\left(\frac{1}{3}-1\right).....\left(\frac{1}{100}-1\right)\)
c,\(\frac{3}{2^2}.\frac{8}{3^2}.\frac{15}{4^2}....\frac{899}{30^2}\)
AI CÒN THỨC THÌ GIÚP MIK VS,MIK ĐANG CẦN GẤP
\(a,\left(\dfrac{37}{9}+\dfrac{13}{4}\right)x\dfrac{9}{4}+\dfrac{11}{4}\) b,\(1+\left(\dfrac{9}{10}-\dfrac{-4}{5}\right):\dfrac{19}{6}\)
c,\(\dfrac{1}{4}-\dfrac{3}{2}+\dfrac{1}{2}x\dfrac{12}{5}\)
Giúp mik nha:>
c) \(\dfrac{\left(2^4.3^5\right)^3.49^{15}-31.6^{12}.9.\left(7^7\right)^4}{2^{11}.21^{14}.343^5+\left(2^4.3^5.7^{10}\right)^3}\)
giúp minh với các bạn ơi. huhu ai đúng mình tích cho nhé
Tìm x:
\(\left(x^2-1\right)^2=9\)
\(12:\left\{390:\left[5.10^2-\left(5^3+x.7^2\right)\right]\right\}=4\)
\(5^3.\left(3x+2\right):13=10^3:\left(13^5:13^4\right)\)
Giúp mik vs nha m.n!>.<
\(9^2.9^{10}\)
\(99.10:10.100\)
tích mik nhae
mik sẽ tích lại
a, \(x-\left[\frac{17}{2}-\left(\frac{-3}{7}+\frac{5}{3}\right)\right]=\frac{-1}{3}\)
b,\(\frac{9}{2}-\left[\frac{2}{3}-\left(x-\frac{7}{4}\right)\right]=\frac{-5}{4}\)
giúp mik với nhé !!! bài khó mik ko làm đc
Tìm x thuộc N
\(a,\left(x-9\right)^4=\left(x-9\right)^7\)
\(b,\left(3x-15\right)^{10}=\left(3x-15\right)^{15}\)
\(c,\left(x-8\right)^3=\left(x-8\right)^6\)
câu nò đúng mik sẽ cho 5 tick nhé
Tối giản phân số sau bằng cách thuận tiện:
\(\frac{\left(2^4+2^2+1\right)\left(4^4+4^2+1\right)\left(6^4+6^2+1\right)\left(8^4+8^2+1\right)\left(10^4+10^2+1\right)}{\left(3^4+3^2+1\right)\left(5^4+5^2+1\right)\left(7^4+7^2+1\right)\left(9^4+9^2+1\right)\left(11^4+11^2+1\right)}\)
