\(92-\left(2\cdot x+4\right)\cdot9=15\cdot2+6\)
\(92-\left(2x+4\right)\cdot9=36\)
\(\left(2x+4\right)\cdot9=92-36\)
\(\left(2x+4\right)\cdot9=56\)
\(2x+4=\frac{56}{9}\)
\(2x=\frac{56}{9}-4\)
\(2x=\frac{20}{9}\)
\(x=\frac{10}{9}\)
tính nhanh:
\(\frac{1\cdot2\cdot3+2\cdot4\cdot6+3\cdot6\cdot9+4\cdot8\cdot12}{1\cdot3\cdot4+4\cdot6\cdot8+6\cdot9\cdot12+8\cdot12\cdot16}\)
dấu \(\cdot\)là dấu nhân nha!
\(\left(\frac{1}{1\cdot3}+\frac{1}{3\cdot5}+\frac{1}{5\cdot7}+\frac{1}{7\cdot9}\right)\cdot\left(x-\frac{1}{2}\right)=\frac{3}{4}\)
Tính nhanh:
\(987654321\cdot\frac{1+1\cdot2+2\cdot3+3\cdot4+4\cdot5+5\cdot6+6\cdot7+7\cdot8+8\cdot9+9\cdot...\cdot999+999\cdot1000+1000}{1000+1000\cdot1001+1001\cdot1002+1002\cdot1003+1003\cdot1004+1004\cdot1005+1005\cdot...\cdot9999+9999\cdot10000+10000}\)
tính nhanh]
b)\(\frac{1\cdot10+2\cdot19+3\cdot18+4\cdot17+.....+18\cdot3+19\cdot2+20\cdot1}{20\cdot\left(1+2+3+.....+19+20\right)-\left(1\cdot2+2+3+3\cdot4+.....+19\cdot20\right)}\)
\(\left(x.1+1\right)+\left(x\cdot2+4\right)+\left(x\cdot3+7\right)+...+\left(x\cdot n+28\right)=200\)
Đề bài là tìm \(x\)
1) Tính
a)\(\frac{13}{15}+\frac{13}{35}+\frac{13}{63}+\frac{13}{99}\)
b)\(\left(\frac{15}{1\cdot2\cdot3}+\frac{15}{2\cdot3\cdot4}+\frac{15}{3\cdot4\cdot5}+.....+\frac{15}{18\cdot19\cdot20}\right)\cdot x=1\)
Trường THCS Lý Tự Trọng
Đề thi khảo sát chọn lớp dành cho học sinh thi vào lớp 6 môn toán
Bài 1 : Tính ( tính nhanh nếu có thể )
a) 1001 x 789 + 456 x 128 - 789 + 912 x 436
b) \(\left(2016\cdot2017+2017\cdot2018\right)\cdot\left(1+\frac{1}{2}:1\frac{1}{2}-1\frac{1}{3}\right)\)
c) \(5\frac{9}{10}:\frac{3}{2}-\left(2\frac{1}{3}\cdot4\frac{1}{2}-2\cdot2\frac{1}{3}\right):\frac{7}{4}\)
Tìm a biết: \(\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+\frac{1}{4\cdot5}+...+\frac{1}{a\cdot\left(a+1\right)}=\frac{49}{100}\)
a)\(\frac{11}{9}+\frac{7}{6}\cdot\left(2-\frac{1}{3}\right)\)
b)\(1\frac{1}{21}:\left(15,75-15\frac{1}{4}\right)+2\frac{1}{12}:\left(7\frac{3}{4}-7,25\right)\)
