tìm X
\(\frac{X+2}{327}+\frac{X+3}{326}+\frac{X+4}{325}+\frac{X+5}{324}+\frac{X+349}{5}=0\)
bài 2
tìm x,y biết
5/X + Y/4 =1/8
x+2/327+x+3/326+x+4/325+x+5/324+x+349/5=4
tìm x biết x+2/327+x+3/326+x+4/325+x+5/324=-4
tìm x biết x+2/327+x+3/326+x+4/325+x+5/324=-4 vậy x=
tìm x, biết :
(x+2)/327 + (x+3)/326 + (x+4)/325 + (x+5)/324 = -4
\(\frac{x+2}{327}+\frac{x+3}{326}+\frac{x+4}{325}+\frac{x+4}{324}+\frac{x+324}{5}=0\)
Tìm x
cho B= 1\ 2(n-1)^2 +3 để tìm GTLN
a, x+2\327 + x+3\326 + x+4\325 + x+5\324 + x+349\5 =0
b, 2a+9\a+3 + 5a+17\a+3 - 3a\a+3 là số nguyên
Tìm x:
a,x-3/97+x-2/98=x-1/99+x/100
b,x+2/327+x+3/326+x+4/325+x+5/324+xx349/5=0
c,(1/1.2+1/2.3+...+1/99.100)-2x=1/2
tìm x biết: (x+2)/327+(x+3)/326+(x+4)/325+(x+5)/324+(x+329)/5 = -4