(8x - 1)2x + 1 = 52x + 1
=> 8x - 1 = 5
=> x = 3/4
\(\left(8x-1\right)^{2x}+1=5^{2x}+1\)
\(\Rightarrow8x-1=5\)
\(8x=6\)
\(x=\frac{3}{4}\)
\(a,\left(8x-1\right)^{2x}+1=5^{2x}+1\)
\(\left(8x-1\right)^{2x}=5^{2x
}\)
\(8x-1=5\)
\(8x=5+1
\)
\(8x=6\)
\(x=\frac{6}{8}\)
Vậy x=\(\frac{6}{8}\)