\(8.\frac{1}{2}-x=\frac{49}{65}.\frac{5}{7}\)
\(4-x=\frac{7}{13}\)
\(x=4-\frac{7}{13}\)
\(x=\frac{45}{13}\)
Học tốt
đề phải như này không ạ
\(8.\frac{1}{2}-x=\frac{49}{65}.\frac{5}{7}\)
\(< =>\frac{8}{2}-x=\frac{49}{65}.\frac{5}{7}\)
\(< =>\frac{8}{2}-\frac{2x}{2}=\frac{7.7.5}{13.5.7}\)
\(< =>\frac{8-2x}{2}=\frac{7}{13}\)
\(< =>\left(8-2x\right)13=14\)
\(< =>8-2x=\frac{14}{13}\)
\(< =>-2x=\frac{14}{13}-8=-\frac{90}{13}\)
\(< =>x=\frac{45}{13}\)
8×1/2-x=49/65×5/7
8×1/2-x=7/13
1/2-x=7/13:8
1/2-x=7/104
x=1/2-7/104
x=45/104
vậy x=45/104
\(8\cdot\frac{1}{2}-x=\frac{49}{65}\cdot\frac{5}{7}\)
\(\frac{8}{2}-x=\frac{245}{455}\)
\(4-x=\frac{7}{13}\)
\(x=4-\frac{7}{13}\)
\(x=3\frac{6}{13}\)
8×1/2-x=49/65×5/7
8×1/2-x=7/13
4-x=7/13
x=4-7/13
x=45/13
vậy x=45/13
\(8\times\frac{1}{2}-x=\frac{49}{65}\times\frac{5}{7}\)
\(4-x=\frac{7}{13}\)
\(x=\frac{45}{13}\)
Vậy : \(x=\frac{45}{13}\)