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\(\frac{8-x}{\left(x+2\right)\left(x-3\right)}+\frac{2}{x+2}=\frac{8-x+2\left(x-3\right)}{\left(x+2\right)\left(x-3\right)}\)\(=\frac{8-x+2x-6}{\left(x+2\right)\left(x-3\right)}=\frac{2+x}{\left(x+2\right)\left(x-3\right)}=\frac{x+2}{\left(x+2\right)\left(x-3\right)}=\frac{1}{x-3}\)
Phân tích đa thức thành nhân tử:
1.45+x^3-5*x^2-9*x
2.x^4-2*x^3-2*x^2-2*x+3
3.x^4-5*x^2+4
4.x^4+64
5.x^5+x^4+1
6.(x^2+2*x)*(x^2+2*x+4)+3
7.(x^3+4*x+8)^2+3*x*(x^2+4*x+8)+2*x^2
8. x^3*(x^2-7)^2-36*x
9.x^5+x+1
10. x^8+x^4+1
11. x^5-x^4-x^3-x^2-x-2
12. x^9-x^7-x^6-x^5+x^4+x^3+x^2-1
13. (x^2-x)^2-12*(x^2-x)+24
tìm x,biết:
a, 3(x-3)-6x=0
b, 2x(x-15)+2x
c, 2(x-3)+3x=9
d, x(x-11)+2(x-11)=0
e,x(x+2)+8=x^2
f, 8(x+1)+2x=-2
g,12-3(x+2)=0
Rút gọn 1) (x-2)^2 - (x+1) (x-1)
2)(3x-2) (3x+2)-(3x+1)^2
3)(x-8) (x+8)-(x+3)^2
4) (2x+y)^2 -2(4x^2-y^2)+(2x-y)^2
Bài 2 tìm x
a) (x+3)^2 - (x-2) (x+2)=8
b) (x-5)^2 - 9 =0
Bài 3 so sánh
A=(2+1) (2^2+1) (2^4+1) (2^8+1) và B = 2^16 .
Phân tích đa thức thành nhân tử.
1)x^4+2x^3-4x-4
2)(x+2)(x+4)(x+6)(x+8)+16
3)(x^2+x).(x^2+x+1)-6
4)(x^2+4x+8)^2+3x(x^2+4x+8)
13-(3.x^2+5x-8).(2x-1)=(-2.x^2-3.x+1).(x+3/8).6.x
tính gt biểu thức
a)P=(x^3+6x^2+12x+8)+3(x^2+4x+4)y+3(x+2)y^2+y^3 với x+y=8
b)Q=(x-1)^3-4x(x+1)(x-1)+3(x-1)(x^2+x+1) với x=-2
I) phan tich
1, 3x^2 - 11x+6
2, 8x^2 + 10x-3
3, 9x^2-9xy-xy
4, x^3+x+2
5, x^8y^8+x^4y^4 + 1
6, x^5+x^4+1
7, x^8+x^2+1
8, x^8+x+1
a, 1/x-1 + 2/x^2+x+1 = 3x^2/x^2-1
c, x/2(x-3) + x/2(x+1 ) = 2x/(x+1 )(x-3)
b, 8-x/x-7 - 8 = 1/1-7
Tìm x, biết:
a) (2x + 1)^2 - 4(x + 2)^2 = 9
b) (x + 3)^2 - (x - 4)( x + 8) = 1
c) 3(x + 2)^2 + (2x - 1)^2 - 7(x + 3)(x - 3) = 36
d)(x - 3)(x^2 + 3x + 9) + x(x + 2)(2 - x) = 1
a) (X-2)(x+3)-3(4x-2)=(x-4)\(^{^{ }2}\)
b) \(\dfrac{2x^2+1}{8}-\dfrac{7x-2}{12}=\dfrac{x^2-1}{4}-\dfrac{x-3}{6}\)
c) \(x-\dfrac{2x-2}{5}+\dfrac{x+8}{6}=7+\dfrac{x-1}{3}\)
d) \(\left(2x+5\right)^2=\left(x+2\right)^2\)
e) \(x^2-5+6=0\)
g) \(2x^3+6x^2=x^2+3x\)
h) \(\left(x+\dfrac{1}{2}\right)^2+2\left(x+\dfrac{1}{x}\right)-8=0\)
mọi người giúp e với ạ
