\(8-2x^2+4xy-2y^2\)
\(=2\left(4-x^2+2xy-y^2\right)\)
\(=2.\left[4-\left(x^2-2xy+y^2\right)\right]\)
\(=2.\left[2^2-\left(x-y\right)^2\right]\)
\(=2\left(2-x+y\right)\left(2+x-y\right)\)
8 - 2x2 + 4xy - 2y2
= 2 (4 - x2 + 2xy - y2)
= 2 [4 - (x2 - 2xy + y2)]
= 2 [4 - (x - y)2 ]
= 2 [ 22 - (x - y)2 ]
= 2 (2 - x + y) (2 + x - y)
= 2 (-x + y + 2) (x - y + 2)
t i c k nhé!! 35345445647567887987790245255415364765756758768