\(8-2x>0\)
\(-2x>-8\)
\(x< 4\)
(Nhớ k cho mình với nha!)
Vì 8-2x>0 nên 2x<8=2.4
Suy ra:x<4
Vậy x thuộc {0;1;2;3}
1.
a.|2x+4|+|4x+8|=0|2x+4|+|4x+8|=0
b.|x−5|+|x−7|=0|x−5|+|x−7|=0
c.|x+8|−|2x+2|=0
tìm STN x
2x + 69 . 2 = 69 . 4
2x - 12 - x = 0
(x-7) . (2x - 8) = 0
Tìm số nguyên x, sao cho :
b) (4-2x) . (x+3)=0
c) -x . ( 8-2x)=0
d) (2x-6) . ( x-3)=0
Mấy bạn giúp mk nha !!!!
(2x2 - 8).2x.(9- x)bằng 0
Tìm x:
(x - 2).(x^2 +1)=0
(x^3+8).(2x^2-8)=0
tim x biet:a.2x^2-1=17/8;b.(2x-0,05)(x+3)>0;c.(7-x)(x+19)>0
tìm x
( 3x - 15 )(10 - x)<0
( 2x - 8 ) (6 - x )≥0
( 15 - 5x ) ( 2x - 4)<0
(6-2x).(x-8)=0
Tìm x : 2x - 12 - x =0
( x - 7) . ( 2x - 8) = 0
(2x-5)3=152-4.52
(x-2)(15-3x)=0
(x-5)-(2x+7)= -8
