\(\frac{7}{12}-0,75:\left(4x-3\right)^2=\frac{-3}{2}\)
\(\frac{3}{4}:\left(4x-3\right)^2=\frac{25}{12}\)
\(\left(4x-3\right)^2=\frac{9}{25}=\left(\frac{\pm3}{5}\right)^2\)
+) 4x - 3 = 3/5
4x = 18/5
x = 9/10
+) 4x - 3 = -3/5
4x = 12/5
x = 3/5
Vậy,.........
\(\frac{7}{12}-0,75:\left(4x-3\right)^2=-\frac{3}{2}\)
\(\Leftrightarrow\frac{7}{12}.12\left(4x-3\right)^2-\frac{0,75}{\left(4x-3\right)^2}.12\left(4x-3\right)^2=-\frac{3}{2}.12\left(4x-3\right)^2\)
\(\Leftrightarrow7\left(4x-3\right)^2-9=-18\left(4x-3\right)^2\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{9}{10}\\x=\frac{3}{5}\end{cases}}\)
\(\frac{7}{12}-0,75:\left(4x-3\right)^2=\frac{-3}{2}\)
\(0,75:\left(4x-3\right)^2=\frac{7}{12}-\frac{-3}{2}\)
\(0,75:\left(4x-3\right)=\frac{7+18}{12}\)
\(0,75:\left(4x-3\right)=\frac{25}{12}\)
\(\frac{3}{4}:\left(4x-3\right)=\frac{25}{12}\)
\(4x-3=\frac{3}{4}:\frac{25}{12}\)
\(4x-3=\frac{3.12}{4.25}=\frac{9}{25}\)
\(4x=\frac{9}{25}+3\)
\(4x=\frac{9+75}{25}\)
\(4x=\frac{84}{25}\)
\(x=\frac{84}{25}:4\)
\(x=\frac{84.1}{25.4}\)
\(x=\frac{21}{25}\)
Vậy \(x=\frac{21}{25}\)
Sửa: ...
\(\left(4x-3\right)^2=\frac{9}{25}\)
\(\left(4x-3\right)^2=0,36\)
\(\left(4x-3\right)^2=\left(0,6\right)^2\)
\(=>4x-3=0,6\)
\(4x=3,6\)
\(x=3,6:4\)
\(x=0,9\)
Vậy x = 0,9
