\(\dfrac{6}{x}+\dfrac{1}{2}=2\)
\(\dfrac{6}{x}=2-\dfrac{1}{2}\)
\(\dfrac{6}{x}=\dfrac{3}{2}\)
\(3x=12\)
\(x=4\)
`6/x + 1/2 = 2` (` x ne 0`)
`=> 6/x = 2- 1/2`
`=> 6/x=3/2`
`=> x= 6 : 3/2`
`=> x= 6 . 2/3`
`=> x=4` (thỏa mãn ĐK)
Vậy `x =4`
\(\dfrac{6}{x}\) + \(\dfrac{1}{2}\)= 2
\(\dfrac{6}{x}\) = 2- \(\dfrac{1}{2}\)
\(\dfrac{6}{x}\) = 3/2
\(\dfrac{3x2}{2x2}\)= 6/x = 4
\(\dfrac{6}{x}\)
6x+12=26x+12=2
6x=2−126x=2−12
6x=326x=32
3x=123x=12
x=4
tui ko bít kb
\(\dfrac{6}{x}\)+12=2
\(\dfrac{6}{x}\)=2-\(\dfrac{1}{2}\)
\(\dfrac{6}{x}\)=\(\dfrac{3}{2}\)
3x=12
x=4
tui ko biết kb