\(\frac{60}{x+5}+\frac{60}{x-4}=\frac{120}{x}\Rightarrow\frac{1}{x+5}+\frac{1}{x-4}=\frac{2}{x}\)
\(\Rightarrow\frac{x\left(x-4\right)+x\left(x+5\right)-2\left(x+5\right)\left(x-4\right)}{x\left(x+5\right)\left(x-4\right)}=0\)
\(\Rightarrow\frac{x^2-4x+x^2+5x-2x^2-2x+40}{x\left(x+5\right)\left(x-4\right)}=0\)
\(\frac{-x+40}{x\left(x+5\right)\left(x-4\right)}=0\)
mà x(x+5)(x-4) khác 0 nên
-x+40=0
nên x=40
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