\(60\%x+\frac{2}{3}x=\frac{1}{3}\cdot\frac{19}{3}\)
\(\Rightarrow\frac{3}{5}x+\frac{2}{3}x=\frac{19}{9}\)
\(\Rightarrow(\frac{3}{5}+\frac{2}{3})x=\frac{19}{9}\)
\(\Rightarrow\frac{19}{15}x=\frac{19}{9}\)
\(\Rightarrow x=\frac{19}{9}:\frac{19}{15}=\frac{95}{57}\)
Vậy \(x=\frac{95}{57}\)