\(6060\frac{50x+20}{x}=101\)
\(\Rightarrow\frac{6060x+50x+20}{x}=101\)
\(\Rightarrow\frac{6110x+20}{x}=101\)
\(\Rightarrow6110x+20=101x\)
\(\Rightarrow6110x-101x=-20\)
\(\Rightarrow6009x=-20\)
\(\Rightarrow x=-\frac{20}{6009}\)
\(6060\frac{50x+20}{x}=101\)
\(\Rightarrow\frac{6060x+50x+20}{x}=101\)
\(\Rightarrow\frac{6110x+20}{x}=101\)
\(\Rightarrow6110x+20=101x\)
\(\Rightarrow6110x-101x=-20\)
\(\Rightarrow6009x=-20\)
\(\Rightarrow x=-\frac{20}{6009}\)
6060÷[(50x+20)÷x]=101
Tìm x
6060 . \(\frac{50x+20}{x}\)= 101
6060/50x+20 phan x =101 hay tim con x do
tìm x
6060*50x+20/x=101
Tìm x biết 6060 . \(\frac{50.x+20}{x}\) = 101
6060 : ( (50 : x + 20) : x) = 101
giải chi tiết hộ em với ạ
em cảm ơn trước ạ
\(\text{Tìm x , biết : }\)
\(a.\frac{1}{5.8}+\frac{1}{8.11}+\frac{1}{11.14}+...+\frac{1}{x\left(x+3\right)}=\frac{101}{1540}\)
\(b.x-\left(\frac{50x}{100}+\frac{25x}{200}\right)=\frac{45}{4}\)
\(c.1+2+3+4+...+x=820\)
Ai làm nhanh mk cho 20 tích
1)Tính nhanh
a) (56.27+56.35):62
b)884.48-432:96/864.48.432
c)45.16-17/28+45.15
d)27.45+27.55/2+4+6+........+18
2) Tìm X thuộc N , biết:
a)[(6.X-39):3].28=5628
b)(16.15):2=(X+70).14-20
c)6060:50.X+20/X=101
So sánh A = \(\frac{20^{102}+1}{20^{101}+1}\) và B = \(\frac{20^{101}+1}{20^{100}+1}\)