\(5x\left(2x-\frac{1}{2}\right)+2\left(2x-\frac{1}{2}\right)=0\)
\(\Rightarrow\left(5x+2\right)\left(2x-\frac{1}{2}\right)=0\)
\(\Rightarrow\orbr{\begin{cases}5x+2=0\\2x-\frac{1}{2}=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=-\frac{2}{5}\\x=\frac{1}{4}\end{cases}}\)
\(5x\left(2x-\frac{1}{2}\right)+2\left(2x-\frac{1}{2}\right)=0\)
\(\left(2x-\frac{1}{2}\right)\left(5x+2\right)=0\)
\(\Rightarrow\orbr{\begin{cases}2x-\frac{1}{2}=0\\5x+2=0\end{cases}\Leftrightarrow\orbr{\begin{cases}2x=\frac{1}{2}\\5x=-2\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=\frac{1}{4}\\x=-\frac{2}{5}\end{cases}}}\)
Vậy \(x=\frac{1}{4}\)hoặc \(x=-\frac{2}{5}\)
\(5x\left(2x-\frac{1}{2}\right)+2\left(2x-\frac{1}{2}\right)=0\)
\(\Leftrightarrow\left(2x-\frac{1}{2}\right)\left(5x+2\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}2x-\frac{1}{2}=0\\5x+2=0\end{cases}\Leftrightarrow\orbr{\begin{cases}2x=\frac{1}{2}\\5x=-2\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=\frac{1}{4}\\x=\frac{-2}{5}\end{cases}}}\)
Vậy x = 1/4 hoặc x = -2/5
\(5x\left(2x-\frac{1}{2}\right)+2\left(2x-\frac{1}{2}\right)=0\)
\(\rightarrow\left(2x-\frac{1}{2}\right)\left(5x+2\right)=0\)
\(\rightarrow\orbr{\begin{cases}2x-\frac{1}{2}=0\\5x+2=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}2x=\frac{1}{2}\\5x=-2\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=\frac{1}{4}\\x=-\frac{2}{5}\end{cases}}\)
Vậy : x = \(\frac{1}{4}\)hoặc x = \(-\frac{2}{5}\)
\(5x\left(2x-\frac{1}{2}\right)+2\left(2x-\frac{1}{2}\right)=0\)
\(\Leftrightarrow\left(2x-\frac{1}{2}\right)\left(5x+2\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}2x-\frac{1}{2}=0\\5x+2=0\end{cases}\Leftrightarrow\orbr{\begin{cases}2x=0+\frac{1}{2}\\5x=0-2\end{cases}\Leftrightarrow}\orbr{\begin{cases}2x=\frac{1}{2}\\5x=-2\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=\frac{1}{2}:2\\x=-2:5\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=\frac{1}{2}\cdot\frac{1}{2}\\x=\frac{-2}{5}\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=\frac{1}{4}\\x=\frac{-2}{5}\end{cases}}}\)
Vậy \(x=\frac{1}{4};x=\frac{-2}{5}\)
