\(5^{x+1}=125\)
\(\Rightarrow5^x.5=125\)
\(\Rightarrow5^x=125:5=25\)
\(\Rightarrow5^x=5^2\Leftrightarrow x=2\)
Ta có: \(5^3=125\) \(\Rightarrow x+1=3\Rightarrow x=2\)
Vậy \(x=2\)
5^x + 1 = 5^3
x + 1 = 3 => x = 2
tích mk nha
\(5^{x+1}=125\)
\(5^{x+1}=5^3\)
\(\Rightarrow x+1=3\)
\(x=3-1\)
\(x=2\)
\(5^{x+1}=125\Rightarrow5^x.5=125\Rightarrow5^x=25\Rightarrow x=2\)
\(5^{x+1}=125\)
\(\Rightarrow5^{x+1}=5^3\)
\(\Rightarrow x+1=3\)
\(\Rightarrow x=2\)
Vậy x=2
Nhớ k mik nha
\(5^{x+1}=125\)
\(\Leftrightarrow5^{x+1}=5^3\)
\(\Rightarrow x+1=3\)
\(\Rightarrow x=2\)
hok tốt!
\(5^{x+1}=125\)
\(\Rightarrow5^{x+1}=5^3\)
\(\Rightarrow x+1=3\)
\(\Rightarrow x=3-1\)
\(\Rightarrow x=2\)
Vậy \(x=2\)