( 5x +3 )2 = -25
( 5x+3)2=52 hoặc ( 5x+3)2=(-5)2
Vì 5x+3 khác 0 nên 5x+3=5 hoặc 5x+3 = -5
Nếu 5x+3 =5
5x=5-3
5x = 2
x=2:5
x=\(\frac{2}{5}\)
Nếu 5x+3=-5
5x = ( - 5)- 3
5x = -8
x= -8 : 5
x =\(\frac{-8}{5}\)
x = \(-1\frac{3}{5}\)
Vậy x = \(\frac{2}{5}\); x = \(-1\frac{3}{5}\)
Tìm x biết:
a) (2x + 3)/(5x +2) = (4x + 5)/(10x + 2)
b) (3x - 1)/(40 - 5x) = (25 - 3x)/(5x - 34)
a) (3x — 1) ^4 = 1/16
b) (5x — 2 )^2 = 25/121
c) (5x + 6)^3= -8/27
Tìm x biết:
a) (2x + 3)/(5x + 2) = (4x +5)/(10x + 2)
b) (3x - 1)/(40 - 5x) = (25 - 3x)/(5x - 34)
Cần giúp gấp
tìm x: 3/5x-25/4=1/2:x+5/4
a) 2x×3/5-5x=3/2-7x
b) (x-1/5)^2=4/25
Tìm x:
a, \(\frac{2x+3}{5x+2}=\frac{4x+5}{10x+2}\)
b,\(\frac{3x-1}{40-5x}=\frac{25-3x}{5x-34}\)
tìm x :
a) 3x-3^2=25
b)2x-3^5=-243
c)5x+2^-1=3^-2
tìm đa thức M
a M + (5x^2 - 2xy) = 6x^2 + 9xy - y^2
b (25 x^2y-13xy^2 + y^3)-M= 11 xy^2 - 2y^3
a, \(\frac{2x+3}{5x+2}\) =\(\frac{4x+5}{10x+2}\)
b, \(\frac{3x-1}{40x-5x}\) =\(\frac{25-3x}{5x-34}\)
