\(\frac{5}{6}.\frac{2}{3}+\frac{3}{2}.\frac{3}{5}+\frac{46}{5}\)
\(=\frac{5}{9}+\frac{9}{10}+\frac{46}{5}\)
\(=\frac{50}{90}+\frac{81}{90}+\frac{828}{90}\)
\(=\frac{959}{90}\)
ta có\(\frac{5}{6}\)* \(\frac{2}{3}\)+\(\frac{3}{2}\)*\(\frac{3}{5}\)+\(\frac{46}{5}\)=\(\frac{10}{18}\)+\(\frac{6}{10}\)+\(\frac{92}{10}\)=\(\frac{98}{10}\)+\(\frac{10}{18}\)=10\(\frac{16}{45}\)