\(\frac{5}{2.5}+\frac{5}{5.8}+......+\frac{5}{98.101}\)
\(=\frac{5}{3}.\left(\frac{3}{2.5}+\frac{3}{5.8}+.........+\frac{3}{98.101}\right)\)
\(=\frac{5}{3}.\left(\frac{1}{2}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}+........+\frac{1}{98}-\frac{1}{101}\right)\)
\(=\frac{5}{3}.\left(\frac{1}{2}-\frac{1}{101}\right)=\frac{5}{3}.\frac{99}{202}\)
\(=\frac{5.33}{202}=\frac{165}{202}\)