\(-5\left(2-\chi\right)+4\left(\chi-3\right)=10\chi-15\)
\(\Rightarrow-10+5\chi+4\chi-12=10\chi-15\)
\(\Rightarrow-10-12+15=10\chi-5\chi-4\chi\)
\(\Rightarrow\chi=-7\)
HTDT
\(-5\left(2-x\right)+4\left(x-3\right)=10x-15\)
\(\Rightarrow-10+5x+4x-12=10x-15\)
\(\Rightarrow-10-12+15=10x-5x-4x\)
\(\Rightarrow x=\left(-7\right)\)
\(2\left(4x-8\right)-7\left(3+x\right)=4\left(3-2\right)\)
\(\Rightarrow8x-16-21-7x=12-8\)
\(\Rightarrow x=12-8+16+21=41\)
\(-5\left(2-x\right)+4\left(x-3\right)=10x-15\)
\(-10+5x+4x-12=10x-15\)
\(5x+4x-10x=10+12-15\)
\(-1x=7\)
\(x=-7\)
Vậy \(x=-7\)
\(2\left(4\chi-8\right)-7\left(3+\chi\right)=4\left(3-2\right)\)
\(\Rightarrow8\chi-16-21+7\chi=4\)
\(\Rightarrow8\chi+7\chi=4+16+21\)
\(\Rightarrow15\chi=41\)
\(\Rightarrow\chi=\frac{41}{15}\)
HTDT
\(2\left(4x-8\right)-7\left(3+x\right)=4\left(3-2\right)\)
\(8x-16-21-7x=4\)
\(8x-7x=16+21+4\)
\(x=41\)
Vậy \(x=41\)
nè, nếu cảm ơn rồi thì bạn phải k cho mấy bạn ấy chứ
a, -5(2-x)+4(x-3)=10x-15
=> -10+5x+4x-12=10x-15
=>9x-22=10x-15
=> x=-7
b, 2(4x-8)-7(3+x)=4(3-2)
=> 8x-16-21-7x=4
=> x-37=4
=> x=41