\(5\left(x-9\right)=350\)
\(\frac{350}{5}=x-9\)
\(x-9=70\)
\(x=70+9\)
\(x=79\)
5 ( x-9 ) = 350.
=> x - 9 = 350 : 5
=> x - 9 = 70
=> x = 70 + 9
=> x = 79
Vậy x = 79
5 ( x - 9) = 350
x - 9 = 350 : 5
x - 9 = 70
x = 70 + 9
x = 79
5(x-9) = 350 \(\Leftrightarrow\)5x -45 =350 \(\Leftrightarrow\)5x =395 \(\Leftrightarrow\)x= \(\frac{395}{5}\)=79
5 ( x- 9 ) = 350
=> x-9 = 350 : 5 = 70
=> x = 70 + 9
=> x = 79
5 [x - 9]= 350
<=>x - 9 = 70
<=>x = 79
5 ( x - 9 ) = 350
x - 9 = 350 : 5
x - 9 = 70
x = 70 + 9
x = 79
Ta có :
5 ( x- 9 ) = 350
=> x-9 = 350 : 5 = 70
=> x = 70 + 9
=> x = 79
Ta có :
5 ( x- 9 ) = 350
=> x-9 = 350 : 5 = 70
=> x = 70 + 9
=> x = 79
5(x-9)=350
(x-9)=350:5
x-9=70
x=70-9
x=61
\(5\left(x-9\right)=350\)
\(x-9=350:5\)
\(x-9=70\)
\(x=70+9\)
\(x=79\)