\(\left(4x+3\right)\left(4x-3\right)-\left(4x-5\right)^2=46\)
\(\Leftrightarrow\)\(16x^2-9-\left(16x^2-40x+25\right)=46\)
\(\Leftrightarrow\)\(40x-34=46\)
\(\Leftrightarrow\)\(40x=80\)
\(\Leftrightarrow\)\(x=2\)
Vậy...
Tìm x biết : (4x+3)(4x-3)-(4x-5)^2=46
Tìm x biết :
a)\((x+3)^2-\left(2x+1\right).\left(2x-1\right)=22\)
b)\(\left(4x+3\right).\left(4x-3\right)-\left(4x-5\right)^2=46\)
Bài 1: Tìm x
(2x-5)2 - 4(2x-5) + 4 =0
Bài 2: Tính nhẩm:
a) 812
b)992
c)28.3.2
bài 3: Tìm x, biết:
(4x+3).(4x-3) - (4x-5)2 = 46
tìm x
1,(2x+3)^2+(2x+1)(2x-1)=22
2,(4x+3)(4x-3)=46+(4x-5)^2
3,(2x-1)^3-4x^2(2x-3)=5
4,(x+4)^2-(x-1)(x+1)=16
5,(2x-1)^2+(x+3)^2=5(x+7)(x-7)+325
6,(x^2+1)^2-(x^4+x^2+1)(x^2-1)=0
rút gọn biểu thức
a,A=(4x-5)2+(4x+5)2+2.(5+4x)(5-4x)
b,B=(3x-2)2(3x+2)2-2(2x+3)(2x-3)
Tìm Min :
a, Y = (x+2)(x+3)(x+4)(x+5) - 24
b, Y= (4x+1)(4x+2)(4x+3)(4x+4)-3
Tìm x biết
(6-3x)^2-2(3x-6)=0(2x+5)^3-(2x+5)=0(6-4x)^3-(6-4x)=0(5-4x)^2-(4x+5)=0Tìm x biết:
(4x - 3)( 4x + 2) + (4x + 5)(1 - 4x) =2.52
(2x-3)(4x2+4x-5)-(4x2-3x+2)(2x+5)
