4(x−5)−(3x−1)=x−19
⇒4x−20−3x+1=x−19
⇒4x−3x−x=−19+20−1
⇒0x=0
⇒x∈R
Chúc bạn học tốt nhé! ^^
\(\text{4(x-5)-(3x-1)=x-19}\)
\(4x-20-3x+1=x-19\)
\(4x-3x-x=-19-1+20\)
\(0=0??\)
\(4\left(x-5\right)-\left(3x-1\right)=x-19\)
\(\Leftrightarrow4x-20-3x+1=x-1\)
\(\Leftrightarrow-19=-1\) ( vô lí )
Vậy pt vô nghiệm
\(4\left(x-5\right)-\left(3x-1\right)=x-19\)
\(4x-20-3x+1=x-19\)
\(x-19=x-19\)
\(x-x=-19+19\)
\(x=0\)
